A. From algebra we learn:
(101a)2 = 10201 x a2
(102a)2 = 10404 x a2
(103a)2 = 10609 x a2
B. Each one can be multiplied the same way. All follow the form: 10c0d x a2. To compute this there are 3 sets of numbers.
1. The last is a2 x d. Write this down. (Make sure it takes 2 place values). Carry if necessary.
2. The middle is a2 x c. Write this down. (Make sure it takes 2 place values). Carry if necessary.
3. The first is simply a2. Add any carried numbers.
C. Examples:
Ex [1] 7072 = _______
a. 707 = 101 x 7. So 72 = 49.
b. The last digits are 49 x 1 = 49. Write 49.
c. The middle digits are 49 x 2 = 98. Write 98.
d. The first digits are 49. Write 49.
e. The answer is 499849.
Ex [2] 4082 = ________
a. 408 = 102 x 4. So 42 = 16.
b. The last digits are 16 x 4 = 64. Write 64.
c. The middle digits are 16 x 4 = 64. Write 64.
d. The first digits are 16.
e. The answer is 166464.
Ex [3] 6182 = ________
a. 618 = 103 x 6. So 62 = 36.
b. The last digits are 36 x 9 = 324. Write 24, carry *3.
c. The middle digits are 36 x 6 = 216 + *3 = 219. Write 19, carry *2.
d. The first digits are 36 + *2 = 38.
e. The answer is 381924.