A. This method is simple once we reduce this form:
(10a + b)2 + [10(b-1) + (10-a)]2 = 101(a2 + b2)
B. Using numbers instead of variables we get the following:
1. Square the one’s digit on the left number.
2. Square the ten’s digit on the left number.
3. Add the result of step 1 and step 2.
4. Multiply the result of step 3 by 101 for the answer. See Multiplying by 101.
C. This method is sometimes hard to recognize. If the inside numbers subtract to 1 and the outside numbers add to 10 then you can use this method.
Ex [1] 432 + 262 =_________.
a) 32 + 42 = 9 + 16 = 25.
b) 25 x 101 = 2525.
c) The answer is 2525.
Ex [2] 652 + 572 =_________.
a) If you look at this equation it does not fit the pattern. But if you switch the two numbers it does. So think of this as being 572 + 652.
b) 52 + 72 = 25 + 49 = 74.
c) 74 x 101 = 7474.
d) The answer is 7474.