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_{Subtracting Three Fractions In The Form:}  1  _-    1   _-    1      

                                                                          a               ab         ab²

A.     From algebra we learn: 

1  _-    1   _-   1       ₌  b(b - 1) - 1    

     a                ab             ab²          ab²

B.     Use the following rules: 

1.      Multiply the coefficient ‘b’, by that number minus 1.

2.      Subtract 1 from step 1.  This is the numerator.

3.      The last denominator of the question is the denominator of the answer.

4.      Simplify the fraction if need be.

             _{Ex [1]}  1  _-  1  _-  1  ₌

                       5     15    45                         (fraction).

a)      The coefficient in this case is 3.

b)      3 x (3 – 1) = 6.

c)      6 – 1 = 5.  This is the numerator.

d)      The answer is ⁵/₄₅.  However, we must reduce this fraction to ¹/₉.

e)   The final answer is ¹/₉.

_{Ex [2]}   1  _-  1  _-  1  ₌

           2     10    50                         (fraction).

   a)      The coefficient in this case is 5.

   b)      5 x (5 – 1) = 20.

   c)      20 – 1 = 19.  This is the numerator

   d)  The answer is ¹⁹/₂₅.

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